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Ah, rotation problem
Author
Since nobody ever answers these, I''ll try again. I have two points. I want to know the rotation around the y & z axes which would be applied to a line from point 1 to pass through point two. My code is as follows:
rotation[Z] = atanf( ( p2[Y] - p1[Y] )/( p2[X] - p1[X] ) );
rotation[Y] = atanf( ( p2[Z] - p1[Z] )/( p2[X] - p1[X] ) );
Is that right?
Subtracting the source position from the target position will give you a directed vector pointing from the source to the target (which may need to be normalized).
I.e., in pseudocode terms, you would do this:
Edited by - revolver on July 1, 2000 1:31:12 AM
I.e., in pseudocode terms, you would do this:
vector3 soure, target, dir;dir = target - source; //basic vector subtractiondir.normalize(); Edited by - revolver on July 1, 2000 1:31:12 AM
Author
I know all about vectors, I am essentially finding the vector in my code already, what I want to do is rotate an object so it matches the vector. I want to rotate the object around the y & x axes, so is my code right or does someone know what the correct way of doing this is?
Morgan
Edited by - Morgan on July 1, 2000 11:21:28 AM
Morgan
Edited by - Morgan on July 1, 2000 11:21:28 AM
Hi Morgan
ok i think your code isn''t totaly false but try this:
#define pi 3.141592654
rotation[Z] = ( atanf( ( p2[Y] - p1[Y] )/( p2[X] - p1[X] ) ) ) / 2 / pi * 360 ;
rotation[Y] = ( atanf( ( p2[Z] - p1[Z] )/( p2[X] - p1[X] ) ) ) / 2 / pi * 360 ;
i think it works so
cose these sin cos and tan functions uses rad where 360 degree are 2 * pi. That was my problem but now it works. Don''t now if i''m right but i make it the other way:
(sin((rotation[y])*2*pi/360)); and this works 100% but i don''t now what it''s in your case. Think about it and try. Good luck
)
cu
Shadow
ok i think your code isn''t totaly false but try this:
#define pi 3.141592654
rotation[Z] = ( atanf( ( p2[Y] - p1[Y] )/( p2[X] - p1[X] ) ) ) / 2 / pi * 360 ;
rotation[Y] = ( atanf( ( p2[Z] - p1[Z] )/( p2[X] - p1[X] ) ) ) / 2 / pi * 360 ;
i think it works so
cose these sin cos and tan functions uses rad where 360 degree are 2 * pi. That was my problem but now it works. Don''t now if i''m right but i make it the other way:
(sin((rotation[y])*2*pi/360)); and this works 100% but i don''t now what it''s in your case. Think about it and try. Good luck
)cu
Shadow
Author
Oh, yeah, that''s actually already implemented in my code using a #define macro, but I forgot to include it. But, using arctan for both will provide the right results?
Morgan
Morgan
hi
i thougt the a in atanf stands for cotangens, cose i dont know about this a but if it stands for radiant then you must write:
rotation[Z] = atanf( ( p2[X] - p1[X] )/( p2[Y] - p1[Y] ) ) ;
rotation[Y] = atanf( ( p2[X] - p1[X] )/( p2[Z] - p1[Z] ) ) ;
or not??
cu
Shadow
i thougt the a in atanf stands for cotangens, cose i dont know about this a
but if it stands for radiant then you must write:rotation[Z] = atanf( ( p2[X] - p1[X] )/( p2[Y] - p1[Y] ) ) ;
rotation[Y] = atanf( ( p2[X] - p1[X] )/( p2[Z] - p1[Z] ) ) ;
or not??
cu
Shadow
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