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<snip>int *pHeap = new int;*pHeap = 7;delete pHeap;pHeap = new int;*pHeap = 9;delete pHeap;C++: A Dialog | C++0x Features: Part1 (lambdas, auto, static_assert) , Part 2 (rvalue references) , Part 3 (decltype) | Write Games | Fix Your Timestep!
Quote: Original post by Zahlmanclass Foo { int bar; public: void wibble() { bar = 1; // the usual way this->bar = 1; // making use of the 'this pointer' }};int main() { Foo x, y; x.wibble(); // <-- 'this' points to x y.wibble(); // <-- 'this' points to y}
Quote: Original post by J0BeQuote: Original post by Zahlmanclass Foo { int bar; public: void wibble() { bar = 1; // the usual way this->bar = 1; // making use of the 'this pointer' }};int main() { Foo x, y; x.wibble(); // <-- 'this' points to x y.wibble(); // <-- 'this' points to y}
I find this confusing for the reason that, when you refer to a pointer, you use the -> operator normally, but here, your using the dot . operator when dereferencing wibble ? Why is that?
Is this specific for the this pointer?
Quote: Original post by Alpha_ProgDes
And this is always a pointer, so you always have to use the -> operator.
Quote: Original post by jwalsh
Alpha, I think you should run the C# workshop. [grin]
